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-4x-32=x^2+2x-24
We move all terms to the left:
-4x-32-(x^2+2x-24)=0
We get rid of parentheses
-x^2-4x-2x+24-32=0
We add all the numbers together, and all the variables
-1x^2-6x-8=0
a = -1; b = -6; c = -8;
Δ = b2-4ac
Δ = -62-4·(-1)·(-8)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2}{2*-1}=\frac{4}{-2} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2}{2*-1}=\frac{8}{-2} =-4 $
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